Search a number
-
+
99561244197113 is a prime number
BaseRepresentation
bin10110101000110011101000…
…100110000000000011111001
3111001111221222021212101100222
4112220303220212000003321
5101022202412003301423
6551425445411105425
726654030305304246
oct2650635046000371
9431457867771328
1099561244197113
11297a576087a516
12b1bb7772a2275
13437277b45287a
141a82b0b7d85cd
15b79c3a75a3c8
hex5a8ce89800f9

99561244197113 has 2 divisors, whose sum is σ = 99561244197114. Its totient is φ = 99561244197112.

The previous prime is 99561244197109. The next prime is 99561244197143. The reversal of 99561244197113 is 31179144216599.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 65150678130409 + 34410566066704 = 8071597^2 + 5866052^2 .

It is an emirp because it is prime and its reverse (31179144216599) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 99561244197113 - 22 = 99561244197109 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (99561244197143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49780622098556 + 49780622098557.

It is an arithmetic number, because the mean of its divisors is an integer number (49780622098557).

Almost surely, 299561244197113 is an apocalyptic number.

It is an amenable number.

99561244197113 is a deficient number, since it is larger than the sum of its proper divisors (1).

99561244197113 is an equidigital number, since it uses as much as digits as its factorization.

99561244197113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14696640, while the sum is 62.

The spelling of 99561244197113 in words is "ninety-nine trillion, five hundred sixty-one billion, two hundred forty-four million, one hundred ninety-seven thousand, one hundred thirteen".