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995951149153 is a prime number
BaseRepresentation
bin11100111111000110101…
…00001000000001100001
310112012201112210111021021
432133203110020001201
5112304201443233103
62041311133325441
7131645412042112
oct16374324100141
93465645714237
10995951149153
11354420506374
12141032036881
1372bc1501acc
14362c0818209
151ad91091bbd
hexe7e3508061

995951149153 has 2 divisors, whose sum is σ = 995951149154. Its totient is φ = 995951149152.

The previous prime is 995951149139. The next prime is 995951149211. The reversal of 995951149153 is 351941159599.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 945859337809 + 50091811344 = 972553^2 + 223812^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-995951149153 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 995951149091 and 995951149100.

It is not a weakly prime, because it can be changed into another prime (995951149103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 497975574576 + 497975574577.

It is an arithmetic number, because the mean of its divisors is an integer number (497975574577).

Almost surely, 2995951149153 is an apocalyptic number.

It is an amenable number.

995951149153 is a deficient number, since it is larger than the sum of its proper divisors (1).

995951149153 is an equidigital number, since it uses as much as digits as its factorization.

995951149153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9841500, while the sum is 61.

The spelling of 995951149153 in words is "nine hundred ninety-five billion, nine hundred fifty-one million, one hundred forty-nine thousand, one hundred fifty-three".