Base | Representation |
---|---|
bin | 11101000101000011011… |
… | …01110001000101101110 |
3 | 10112111222011121110110101 |
4 | 32202201231301011232 |
5 | 112332222224320443 |
6 | 2043000124301314 |
7 | 132120520656562 |
oct | 16424155610556 |
9 | 3474864543411 |
10 | 999145541998 |
11 | 35580a679a5a |
12 | 1417839a183a |
13 | 732b02593a6 |
14 | 36504b836a2 |
15 | 1aecb73384d |
hex | e8a1b7116e |
999145541998 has 4 divisors (see below), whose sum is σ = 1498718313000. Its totient is φ = 499572770998.
The previous prime is 999145541981. The next prime is 999145542023. The reversal of 999145541998 is 899145541999.
999145541998 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 899145541999 = 277 ⋅3246012787.
It is a self number, because there is not a number n which added to its sum of digits gives 999145541998.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 249786385498 + ... + 249786385501.
It is an arithmetic number, because the mean of its divisors is an integer number (374679578250).
Almost surely, 2999145541998 is an apocalyptic number.
999145541998 is a deficient number, since it is larger than the sum of its proper divisors (499572771002).
999145541998 is a wasteful number, since it uses less digits than its factorization.
999145541998 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 499572771001.
The product of its digits is 188956800, while the sum is 73.
Subtracting from 999145541998 its reverse (899145541999), we obtain a palindrome (99999999999).
The spelling of 999145541998 in words is "nine hundred ninety-nine billion, one hundred forty-five million, five hundred forty-one thousand, nine hundred ninety-eight".
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