Base | Representation |
---|---|
bin | 1001000101111001100001… |
… | …0101101110100101000001 |
3 | 1022101200212021012110220021 |
4 | 2101132120111232211001 |
5 | 2302242220322333213 |
6 | 33132311044013441 |
7 | 2051153416105663 |
oct | 221363025564501 |
9 | 38350767173807 |
10 | 9996944730433 |
11 | 3204753753851 |
12 | 1155584691281 |
13 | 5769281921cb |
14 | 267bd745a533 |
15 | 12509bad2d8d |
hex | 9179856e941 |
9996944730433 has 2 divisors, whose sum is σ = 9996944730434. Its totient is φ = 9996944730432.
The previous prime is 9996944730397. The next prime is 9996944730439. The reversal of 9996944730433 is 3340374496999.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9431827192384 + 565117538049 = 3071128^2 + 751743^2 .
It is a cyclic number.
It is not a de Polignac number, because 9996944730433 - 225 = 9996911176001 is a prime.
It is not a weakly prime, because it can be changed into another prime (9996944730439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4998472365216 + 4998472365217.
It is an arithmetic number, because the mean of its divisors is an integer number (4998472365217).
Almost surely, 29996944730433 is an apocalyptic number.
It is an amenable number.
9996944730433 is a deficient number, since it is larger than the sum of its proper divisors (1).
9996944730433 is an equidigital number, since it uses as much as digits as its factorization.
9996944730433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 476171136, while the sum is 70.
The spelling of 9996944730433 in words is "nine trillion, nine hundred ninety-six billion, nine hundred forty-four million, seven hundred thirty thousand, four hundred thirty-three".
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