999804052193 has 2 divisors, whose sum is σ = 999804052194. Its totient is φ = 999804052192.

The previous prime is 999804052153. The next prime is 999804052213. The reversal of 999804052193 is 391250408999.

999804052193 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 715727844049 + 284076208144 = 846007^2 + 532988^2 .

It is an emirp because it is prime and its reverse (391250408999) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 999804052193 - 2⁶ = 999804052129 is a prime.

It is not a weakly prime, because it can be changed into another prime (999804052153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499902026096 + 499902026097.

It is an arithmetic number, because the mean of its divisors is an integer number (499902026097).

Almost surely, 2^999804052193 is an apocalyptic number.

It is an amenable number.

999804052193 is a deficient number, since it is larger than the sum of its proper divisors (1).

999804052193 is an equidigital number, since it uses as much as digits as its factorization.

999804052193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6298560, while the sum is 59.

The spelling of 999804052193 in words is "nine hundred ninety-nine billion, eight hundred four million, fifty-two thousand, one hundred ninety-three".