Base | Representation |
---|---|
bin | 11101000110100011010… |
… | …11110010001111100011 |
3 | 10112121001020221212102002 |
4 | 32203101223302033203 |
5 | 112340344241010203 |
6 | 2043212033514215 |
7 | 132146462361026 |
oct | 16432153621743 |
9 | 3477036855362 |
10 | 999950328803 |
11 | 35609298a218 |
12 | 14196941296b |
13 | 733aabc6cba |
14 | 3657d9d71bd |
15 | 1b027203d88 |
hex | e8d1af23e3 |
999950328803 has 2 divisors, whose sum is σ = 999950328804. Its totient is φ = 999950328802.
The previous prime is 999950328781. The next prime is 999950328823. The reversal of 999950328803 is 308823059999.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-999950328803 is a prime.
It is a super-2 number, since 2×9999503288032 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 999950328803.
It is not a weakly prime, because it can be changed into another prime (999950328823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499975164401 + 499975164402.
It is an arithmetic number, because the mean of its divisors is an integer number (499975164402).
Almost surely, 2999950328803 is an apocalyptic number.
999950328803 is a deficient number, since it is larger than the sum of its proper divisors (1).
999950328803 is an equidigital number, since it uses as much as digits as its factorization.
999950328803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 37791360, while the sum is 65.
The spelling of 999950328803 in words is "nine hundred ninety-nine billion, nine hundred fifty million, three hundred twenty-eight thousand, eight hundred three".
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