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999971356673 is a prime number
BaseRepresentation
bin11101000110100101111…
…00000000000000000001
310112121002201112012020002
432203102330000000001
5112340420131403143
62043214104325345
7132150136200542
oct16432274000001
93477081465202
10999971356673
113560a3841823
12141974473855
13733b237a223
143658270c4c9
151b028ea95b8
hexe8d2f00001

999971356673 has 2 divisors, whose sum is σ = 999971356674. Its totient is φ = 999971356672.

The previous prime is 999971356649. The next prime is 999971356679. The reversal of 999971356673 is 376653179999.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 914044987249 + 85926369424 = 956057^2 + 293132^2 .

It is a cyclic number.

It is not a de Polignac number, because 999971356673 - 230 = 998897614849 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 999971356673.

It is not a weakly prime, because it can be changed into another prime (999971356679) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499985678336 + 499985678337.

It is an arithmetic number, because the mean of its divisors is an integer number (499985678337).

It is a Proth number, since it is equal to 953647 ⋅ 220 + 1 and 953647 < 220.

Almost surely, 2999971356673 is an apocalyptic number.

It is an amenable number.

999971356673 is a deficient number, since it is larger than the sum of its proper divisors (1).

999971356673 is an equidigital number, since it uses as much as digits as its factorization.

999971356673 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 520812180, while the sum is 74.

The spelling of 999971356673 in words is "nine hundred ninety-nine billion, nine hundred seventy-one million, three hundred fifty-six thousand, six hundred seventy-three".