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9999899578433 is a prime number
BaseRepresentation
bin1001000110000100100001…
…1101100101000001000001
31022101222111012021022100002
42101201020131211001001
52302314243243002213
633133520200405345
72051316555645122
oct221411035450101
938358435238302
109999899578433
113205a2a684896
12115606a176855
13576ca93c7b8b
14267dd7a6c049
151251c1208658
hex91848765041

9999899578433 has 2 divisors, whose sum is σ = 9999899578434. Its totient is φ = 9999899578432.

The previous prime is 9999899578373. The next prime is 9999899578453. The reversal of 9999899578433 is 3348759989999.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7948210032049 + 2051689546384 = 2819257^2 + 1432372^2 .

It is an emirp because it is prime and its reverse (3348759989999) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-9999899578433 is a prime.

It is a super-2 number, since 2×99998995784332 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (9999899578453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4999949789216 + 4999949789217.

It is an arithmetic number, because the mean of its divisors is an integer number (4999949789217).

Almost surely, 29999899578433 is an apocalyptic number.

It is an amenable number.

9999899578433 is a deficient number, since it is larger than the sum of its proper divisors (1).

9999899578433 is an equidigital number, since it uses as much as digits as its factorization.

9999899578433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 42855402240, while the sum is 92.

The spelling of 9999899578433 in words is "nine trillion, nine hundred ninety-nine billion, eight hundred ninety-nine million, five hundred seventy-eight thousand, four hundred thirty-three".