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999999113 is a prime number
BaseRepresentation
bin111011100110101…
…100011010001001
32120200200012220012
4323212230122021
54021444432423
6243121241305
733531565211
oct7346543211
92520605805
10999999113
11473523153
1223aa93235
1312c239969
1496b4b241
155cbd1078
hex3b9ac689

999999113 has 2 divisors, whose sum is σ = 999999114. Its totient is φ = 999999112.

The previous prime is 999999107. The next prime is 999999131. The reversal of 999999113 is 311999999.

Together with next prime (999999131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 876633664 + 123365449 = 29608^2 + 11107^2 .

It is an emirp because it is prime and its reverse (311999999) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-999999113 is a prime.

It is not a weakly prime, because it can be changed into another prime (999999103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499999556 + 499999557.

It is an arithmetic number, because the mean of its divisors is an integer number (499999557).

Almost surely, 2999999113 is an apocalyptic number.

It is an amenable number.

999999113 is a deficient number, since it is larger than the sum of its proper divisors (1).

999999113 is an equidigital number, since it uses as much as digits as its factorization.

999999113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1594323, while the sum is 59.

The square root of 999999113 is about 31622.7625769793. The cubic root of 999999113 is about 999.9997043332. Note that the first 3 decimals are identical.

The spelling of 999999113 in words is "nine hundred ninety-nine million, nine hundred ninety-nine thousand, one hundred thirteen".