1000000332013 has 2 divisors, whose sum is σ = 1000000332014. Its totient is φ = 1000000332012.

The previous prime is 1000000332007. The next prime is 1000000332017. The reversal of 1000000332013 is 3102330000001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 766917044644 + 233083287369 = 875738^2 + 482787^2 .

It is a cyclic number.

It is not a de Polignac number, because 1000000332013 - 2¹³ = 1000000323821 is a prime.

It is a super-2 number, since 2×1000000332013² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1000000331984 and 1000000332002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1000000332017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500000166006 + 500000166007.

It is an arithmetic number, because the mean of its divisors is an integer number (500000166007).

Almost surely, 2^{1000000332013} is an apocalyptic number.

It is an amenable number.

1000000332013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000000332013 is an equidigital number, since it uses as much as digits as its factorization.

1000000332013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 1000000332013 its reverse (3102330000001), we get a palindrome (4102330332014).

The spelling of 1000000332013 in words is "one trillion, three hundred thirty-two thousand, thirteen".