Search a number
-
+
100001100131 is a prime number
BaseRepresentation
bin101110100100010000…
…1111011000101100011
3100120010020201020100022
41131020201323011203
53114300240201011
6113535002344055
710140056216612
oct1351041730543
9316106636308
10100001100131
11394570176a9
121746a1bb02b
139578b063ca
144ba9269879
1529043a58db
hex174887b163

100001100131 has 2 divisors, whose sum is σ = 100001100132. Its totient is φ = 100001100130.

The previous prime is 100001100083. The next prime is 100001100139. The reversal of 100001100131 is 131001100001.

It is an a-pointer prime, because the next prime (100001100139) can be obtained adding 100001100131 to its sum of digits (8).

It is a strong prime.

It is an emirp because it is prime and its reverse (131001100001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100001100131 is a prime.

It is a super-2 number, since 2×1000011001312 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (100001100139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50000550065 + 50000550066.

It is an arithmetic number, because the mean of its divisors is an integer number (50000550066).

Almost surely, 2100001100131 is an apocalyptic number.

100001100131 is a deficient number, since it is larger than the sum of its proper divisors (1).

100001100131 is an equidigital number, since it uses as much as digits as its factorization.

100001100131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 100001100131 its reverse (131001100001), we get a palindrome (231002200132).

The spelling of 100001100131 in words is "one hundred billion, one million, one hundred thousand, one hundred thirty-one".