Base | Representation |
---|---|
bin | 101110100100010010… |
… | …1110110110101101111 |
3 | 100120010022122121212011 |
4 | 1131020211312311233 |
5 | 3114301021200221 |
6 | 113535040422051 |
7 | 10140101043145 |
oct | 1351045666557 |
9 | 316108577764 |
10 | 100002131311 |
11 | 39457661415 |
12 | 1746a617927 |
13 | 95790a7884 |
14 | 4ba9457595 |
15 | 290450b1e1 |
hex | 1748976d6f |
100002131311 has 4 divisors (see below), whose sum is σ = 105265401400. Its totient is φ = 94738861224.
The previous prime is 100002131309. The next prime is 100002131347. The reversal of 100002131311 is 113131200001.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 100002131311 - 21 = 100002131309 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 100002131291 and 100002131300.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100002131611) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2631635016 + ... + 2631635053.
It is an arithmetic number, because the mean of its divisors is an integer number (26316350350).
Almost surely, 2100002131311 is an apocalyptic number.
100002131311 is a deficient number, since it is larger than the sum of its proper divisors (5263270089).
100002131311 is an equidigital number, since it uses as much as digits as its factorization.
100002131311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5263270088.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 100002131311 its reverse (113131200001), we get a palindrome (213133331312).
The spelling of 100002131311 in words is "one hundred billion, two million, one hundred thirty-one thousand, three hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •