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100010033113 = 5912161139387
BaseRepresentation
bin101110100100100001…
…1111111111111011001
3100120010212112002002111
41131021003333333121
53114310032024423
6113535522032321
710140225153364
oct1351103777731
9316125462074
10100010033113
1139461069131
12174711a86a1
13957a9133b3
144baa5130db
15290506c60d
hex17490fffd9

100010033113 has 8 divisors (see below), whose sum is σ = 101714211360. Its totient is φ = 98306158080.

The previous prime is 100010032999. The next prime is 100010033147. The reversal of 100010033113 is 311330010001.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 100010033113 - 221 = 100007935961 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100010033093 and 100010033102.

It is not an unprimeable number, because it can be changed into a prime (100010433113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 647806 + ... + 787192.

It is an arithmetic number, because the mean of its divisors is an integer number (12714276420).

Almost surely, 2100010033113 is an apocalyptic number.

It is an amenable number.

100010033113 is a deficient number, since it is larger than the sum of its proper divisors (1704178247).

100010033113 is a wasteful number, since it uses less digits than its factorization.

100010033113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 151607.

The product of its (nonzero) digits is 27, while the sum is 13.

Adding to 100010033113 its reverse (311330010001), we get a palindrome (411340043114).

The spelling of 100010033113 in words is "one hundred billion, ten million, thirty-three thousand, one hundred thirteen".

Divisors: 1 59 12161 139387 717499 8223833 1695085307 100010033113