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10001022013 is a prime number
BaseRepresentation
bin10010101000001101…
…10111110000111101
3221210222200120001201
421110012313300331
5130440230201023
64332220335501
7502556166403
oct112406676075
927728616051
1010001022013
114272352954
121b313a4591
13c34c87708
146ac34b473
153d8010bad
hex2541b7c3d

10001022013 has 2 divisors, whose sum is σ = 10001022014. Its totient is φ = 10001022012.

The previous prime is 10001021993. The next prime is 10001022023. The reversal of 10001022013 is 31022010001.

It is an a-pointer prime, because the next prime (10001022023) can be obtained adding 10001022013 to its sum of digits (10).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9175149369 + 825872644 = 95787^2 + 28738^2 .

It is a cyclic number.

It is not a de Polignac number, because 10001022013 - 217 = 10000890941 is a prime.

It is a super-5 number, since 5×100010220135 (a number of 51 digits) contains 55555 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10001022023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000511006 + 5000511007.

It is an arithmetic number, because the mean of its divisors is an integer number (5000511007).

Almost surely, 210001022013 is an apocalyptic number.

It is an amenable number.

10001022013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10001022013 is an equidigital number, since it uses as much as digits as its factorization.

10001022013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 10.

Adding to 10001022013 its reverse (31022010001), we get a palindrome (41023032014).

The spelling of 10001022013 in words is "ten billion, one million, twenty-two thousand, thirteen".