100011011212181 has 2 divisors, whose sum is σ = 100011011212182. Its totient is φ = 100011011212180.

The previous prime is 100011011212067. The next prime is 100011011212183. The reversal of 100011011212181 is 181212110110001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65843081640625 + 34167929571556 = 8114375^2 + 5845334^2 .

It is a cyclic number.

It is not a de Polignac number, because 100011011212181 - 2¹⁰ = 100011011211157 is a prime.

It is a super-2 number, since 2×100011011212181² (a number of 29 digits) contains 22 as substring.

Together with 100011011212183, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100011011212183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50005505606090 + 50005505606091.

It is an arithmetic number, because the mean of its divisors is an integer number (50005505606091).

Almost surely, 2^{100011011212181} is an apocalyptic number.

It is an amenable number.

100011011212181 is a deficient number, since it is larger than the sum of its proper divisors (1).

100011011212181 is an equidigital number, since it uses as much as digits as its factorization.

100011011212181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 20.

Adding to 100011011212181 its reverse (181212110110001), we get a palindrome (281223121322182).

The spelling of 100011011212181 in words is "one hundred trillion, eleven billion, eleven million, two hundred twelve thousand, one hundred eighty-one".