10001111000053 has 2 divisors, whose sum is σ = 10001111000054. Its totient is φ = 10001111000052.

The previous prime is 10001111000033. The next prime is 10001111000113. The reversal of 10001111000053 is 35000011110001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9999749168644 + 1361831409 = 3162238^2 + 36903^2 .

It is a cyclic number.

It is not a de Polignac number, because 10001111000053 - 2⁹ = 10001110999541 is a prime.

It is a super-2 number, since 2×10001111000053² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10001110999997 and 10001111000042.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10001111000033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000555500026 + 5000555500027.

It is an arithmetic number, because the mean of its divisors is an integer number (5000555500027).

Almost surely, 2^{10001111000053} is an apocalyptic number.

It is an amenable number.

10001111000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

10001111000053 is an equidigital number, since it uses as much as digits as its factorization.

10001111000053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 13.

Adding to 10001111000053 its reverse (35000011110001), we get a palindrome (45001122110054).

The spelling of 10001111000053 in words is "ten trillion, one billion, one hundred eleven million, fifty-three", and thus it is an aban number.