100011144013 has 4 divisors (see below), whose sum is σ = 109103066208. Its totient is φ = 90919221820.

The previous prime is 100011143993. The next prime is 100011144019. The reversal of 100011144013 is 310441110001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100011144013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100011144019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4545961081 + ... + 4545961102.

It is an arithmetic number, because the mean of its divisors is an integer number (27275766552).

Almost surely, 2^100011144013 is an apocalyptic number.

It is an amenable number.

100011144013 is a deficient number, since it is larger than the sum of its proper divisors (9091922195).

100011144013 is an equidigital number, since it uses as much as digits as its factorization.

100011144013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9091922194.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 100011144013 its reverse (310441110001), we get a palindrome (410452254014).

The spelling of 100011144013 in words is "one hundred billion, eleven million, one hundred forty-four thousand, thirteen".