Base | Representation |
---|---|
bin | 111011100111001… |
… | …000000000010011 |
3 | 2120200212221221122 |
4 | 323213020000103 |
5 | 4022012042042 |
6 | 243123512455 |
7 | 33532545566 |
oct | 7347100023 |
9 | 2520787848 |
10 | 1000112147 |
11 | 4735a0071 |
12 | 23ab2872b |
13 | 12c279248 |
14 | 96b7a4dd |
15 | 5cc047d2 |
hex | 3b9c8013 |
1000112147 has 2 divisors, whose sum is σ = 1000112148. Its totient is φ = 1000112146.
The previous prime is 1000112129. The next prime is 1000112207. The reversal of 1000112147 is 7412110001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1000112147 - 222 = 995917843 is a prime.
It is not a weakly prime, because it can be changed into another prime (1000112117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500056073 + 500056074.
It is an arithmetic number, because the mean of its divisors is an integer number (500056074).
Almost surely, 21000112147 is an apocalyptic number.
1000112147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000112147 is an equidigital number, since it uses as much as digits as its factorization.
1000112147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 17.
The square root of 1000112147 is about 31624.5497517356. The cubic root of 1000112147 is about 1000.0373809360.
Adding to 1000112147 its reverse (7412110001), we get a palindrome (8412222148).
The spelling of 1000112147 in words is "one billion, one hundred twelve thousand, one hundred forty-seven".
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