Search a number
-
+
10001131442013 = 35956503567469
BaseRepresentation
bin1001000110001001000111…
…1000110000111101011101
31022102002200001020110111010
42101202101320300331131
52302324304122121023
633134242323445433
72051362234423125
oct221422170607535
938362601213433
1010001131442013
113206501a74168
121156352826879
1357714469763a
142680b34d3c85
1512524443a093
hex91891e30f5d

10001131442013 has 8 divisors (see below), whose sum is σ = 13560856192800. Its totient is φ = 6554413826288.

The previous prime is 10001131441997. The next prime is 10001131442017. The reversal of 10001131442013 is 31024413110001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10001131442013 - 24 = 10001131441997 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10001131442017) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28251783558 + ... + 28251783911.

It is an arithmetic number, because the mean of its divisors is an integer number (1695107024100).

Almost surely, 210001131442013 is an apocalyptic number.

It is an amenable number.

10001131442013 is a deficient number, since it is larger than the sum of its proper divisors (3559724750787).

10001131442013 is an equidigital number, since it uses as much as digits as its factorization.

10001131442013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56503567531.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 10001131442013 its reverse (31024413110001), we get a palindrome (41025544552014).

The spelling of 10001131442013 in words is "ten trillion, one billion, one hundred thirty-one million, four hundred forty-two thousand, thirteen".

Divisors: 1 3 59 177 56503567469 169510702407 3333710480671 10001131442013