100012133113 has 2 divisors, whose sum is σ = 100012133114. Its totient is φ = 100012133112.

The previous prime is 100012133107. The next prime is 100012133119. The reversal of 100012133113 is 311331210001.

It is a balanced prime because it is at equal distance from previous prime (100012133107) and next prime (100012133119).

It can be written as a sum of positive squares in only one way, i.e., 68043765904 + 31968367209 = 260852^2 + 178797^2 .

It is a cyclic number.

It is not a de Polignac number, because 100012133113 - 2¹³ = 100012124921 is a prime.

It is not a weakly prime, because it can be changed into another prime (100012133119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50006066556 + 50006066557.

It is an arithmetic number, because the mean of its divisors is an integer number (50006066557).

Almost surely, 2^100012133113 is an apocalyptic number.

It is an amenable number.

100012133113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100012133113 is an equidigital number, since it uses as much as digits as its factorization.

100012133113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 100012133113 its reverse (311331210001), we get a palindrome (411343343114).

The spelling of 100012133113 in words is "one hundred billion, twelve million, one hundred thirty-three thousand, one hundred thirteen".