100012210101143 has 2 divisors, whose sum is σ = 100012210101144. Its totient is φ = 100012210101142.

The previous prime is 100012210101113. The next prime is 100012210101403. The reversal of 100012210101143 is 341101012210001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100012210101143 - 2¹⁰ = 100012210100119 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100012210101113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50006105050571 + 50006105050572.

It is an arithmetic number, because the mean of its divisors is an integer number (50006105050572).

Almost surely, 2^{100012210101143} is an apocalyptic number.

100012210101143 is a deficient number, since it is larger than the sum of its proper divisors (1).

100012210101143 is an equidigital number, since it uses as much as digits as its factorization.

100012210101143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 100012210101143 its reverse (341101012210001), we get a palindrome (441113222311144).

The spelling of 100012210101143 in words is "one hundred trillion, twelve billion, two hundred ten million, one hundred one thousand, one hundred forty-three".