Base | Representation |
---|---|
bin | 11101000110111000100… |
… | …10001000010111010111 |
3 | 10112121111122120021102012 |
4 | 32203130102020113113 |
5 | 112341230301344142 |
6 | 2043241425134435 |
7 | 132154052015042 |
oct | 16433422102727 |
9 | 3477448507365 |
10 | 1000128153047 |
11 | 3561742a6201 |
12 | 1419b8a8a41b |
13 | 734089b874a |
14 | 36599485c59 |
15 | 1b037b2c882 |
hex | e8dc4885d7 |
1000128153047 has 2 divisors, whose sum is σ = 1000128153048. Its totient is φ = 1000128153046.
The previous prime is 1000128152929. The next prime is 1000128153049. The reversal of 1000128153047 is 7403518210001.
1000128153047 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1000128153047 is a prime.
Together with 1000128153049, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1000128153049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500064076523 + 500064076524.
It is an arithmetic number, because the mean of its divisors is an integer number (500064076524).
Almost surely, 21000128153047 is an apocalyptic number.
1000128153047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000128153047 is an equidigital number, since it uses as much as digits as its factorization.
1000128153047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 32.
The spelling of 1000128153047 in words is "one trillion, one hundred twenty-eight million, one hundred fifty-three thousand, forty-seven".
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