Base | Representation |
---|---|
bin | 101110100100100111… |
… | …1010100010110011101 |
3 | 100120011002002211000122 |
4 | 1131021033110112131 |
5 | 3114311312000333 |
6 | 113540105404325 |
7 | 10140262321436 |
oct | 1351117242635 |
9 | 316132084018 |
10 | 100013000093 |
11 | 39462805286 |
12 | 174721996a5 |
13 | 957b4119c6 |
14 | 4baaa8648d |
15 | 2905456798 |
hex | 17493d459d |
100013000093 has 2 divisors, whose sum is σ = 100013000094. Its totient is φ = 100013000092.
The previous prime is 100013000051. The next prime is 100013000207. The reversal of 100013000093 is 390000310001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 97405161604 + 2607838489 = 312098^2 + 51067^2 .
It is a cyclic number.
It is not a de Polignac number, because 100013000093 - 26 = 100013000029 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100013002093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50006500046 + 50006500047.
It is an arithmetic number, because the mean of its divisors is an integer number (50006500047).
Almost surely, 2100013000093 is an apocalyptic number.
It is an amenable number.
100013000093 is a deficient number, since it is larger than the sum of its proper divisors (1).
100013000093 is an equidigital number, since it uses as much as digits as its factorization.
100013000093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 100013000093 its reverse (390000310001), we get a palindrome (490013310094).
The spelling of 100013000093 in words is "one hundred billion, thirteen million, ninety-three", and thus it is an aban number.
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