Base | Representation |
---|---|
bin | 11101000110111000110… |
… | …01100011101100110011 |
3 | 10112121111210020012011021 |
4 | 32203130121203230303 |
5 | 112341231301200034 |
6 | 2043241535000311 |
7 | 132154104404251 |
oct | 16433431435463 |
9 | 3477453205137 |
10 | 1000130100019 |
11 | 356175405a76 |
12 | 1419b9669097 |
13 | 7340921a9bb |
14 | 365998315d1 |
15 | 1b037db46b4 |
hex | e8dc663b33 |
1000130100019 has 2 divisors, whose sum is σ = 1000130100020. Its totient is φ = 1000130100018.
The previous prime is 1000130099989. The next prime is 1000130100049. The reversal of 1000130100019 is 9100010310001.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (1000130099989) and next prime (1000130100049).
It is a cyclic number.
It is not a de Polignac number, because 1000130100019 - 217 = 1000129968947 is a prime.
It is a super-2 number, since 2×10001301000192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1000130099975 and 1000130100011.
It is not a weakly prime, because it can be changed into another prime (1000130100049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500065050009 + 500065050010.
It is an arithmetic number, because the mean of its divisors is an integer number (500065050010).
Almost surely, 21000130100019 is an apocalyptic number.
1000130100019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000130100019 is an equidigital number, since it uses as much as digits as its factorization.
1000130100019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27, while the sum is 16.
The spelling of 1000130100019 in words is "one trillion, one hundred thirty million, one hundred thousand, nineteen".
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