| Base | Representation |
|---|---|
| bin | 10010101000001111… |
| … | …11110010111100000 |
| 3 | 221211000020020202100 |
| 4 | 21110013332113200 |
| 5 | 130440313424300 |
| 6 | 4332230450400 |
| 7 | 502561512456 |
| oct | 112407762740 |
| 9 | 27730206670 |
| 10 | 10001311200 |
| 11 | 4272530151 |
| 12 | 1b31503a00 |
| 13 | c3505922a |
| 14 | 6ac3c49d6 |
| 15 | 3d806b700 |
| hex | 2541fe5e0 |
10001311200 has 432 divisors, whose sum is σ = 38418634800. Its totient is φ = 2438553600.
The previous prime is 10001311189. The next prime is 10001311207. The reversal of 10001311200 is 211310001.
10001311200 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (9).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10001311207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 3965940 + ... + 3968460.
It is an arithmetic number, because the mean of its divisors is an integer number (88932025).
Almost surely, 210001311200 is an apocalyptic number.
10001311200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 10001311200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19209317400).
10001311200 is an abundant number, since it is smaller than the sum of its proper divisors (28417323600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10001311200 is a wasteful number, since it uses less digits than its factorization.
10001311200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2595 (or 2579 counting only the distinct ones).
The product of its (nonzero) digits is 6, while the sum is 9.
Adding to 10001311200 its reverse (211310001), we get a palindrome (10212621201).
It can be divided in two parts, 10001 and 311200, that added together give a triangular number (321201 = T801).
The spelling of 10001311200 in words is "ten billion, one million, three hundred eleven thousand, two hundred".
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