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10001324343 = 35575985233
BaseRepresentation
bin10010101000010000…
…00001100100110111
3221211000020220210010
421110020001210313
5130440314334333
64332231031303
7502561566003
oct112410014467
927730226703
1010001324343
11427253a00a
121b3150b533
13c350621ca
146ac3c9703
153d8070563
hex254201937

10001324343 has 8 divisors (see below), whose sum is σ = 13359042288. Its totient is φ = 6655577984.

The previous prime is 10001324341. The next prime is 10001324413. The reversal of 10001324343 is 34342310001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10001324343 - 21 = 10001324341 is a prime.

It is a super-2 number, since 2×100013243432 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10001324341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2990946 + ... + 2994287.

It is an arithmetic number, because the mean of its divisors is an integer number (1669880286).

Almost surely, 210001324343 is an apocalyptic number.

10001324343 is a deficient number, since it is larger than the sum of its proper divisors (3357717945).

10001324343 is an equidigital number, since it uses as much as digits as its factorization.

10001324343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5985793.

The product of its (nonzero) digits is 864, while the sum is 21.

Adding to 10001324343 its reverse (34342310001), we get a palindrome (44343634344).

The spelling of 10001324343 in words is "ten billion, one million, three hundred twenty-four thousand, three hundred forty-three".

Divisors: 1 3 557 1671 5985233 17955699 3333774781 10001324343