10001340340111 has 4 divisors (see below), whose sum is σ = 10062698256472. Its totient is φ = 9939982423752.

The previous prime is 10001340340063. The next prime is 10001340340139. The reversal of 10001340340111 is 11104304310001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10001340340111 - 2¹⁷ = 10001340209039 is a prime.

It is a super-2 number, since 2×10001340340111² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10001340340811) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30678957936 + ... + 30678958261.

It is an arithmetic number, because the mean of its divisors is an integer number (2515674564118).

Almost surely, 2^{10001340340111} is an apocalyptic number.

10001340340111 is a deficient number, since it is larger than the sum of its proper divisors (61357916361).

10001340340111 is an equidigital number, since it uses as much as digits as its factorization.

10001340340111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61357916360.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10001340340111 its reverse (11104304310001), we get a palindrome (21105644650112).

The spelling of 10001340340111 in words is "ten trillion, one billion, three hundred forty million, three hundred forty thousand, one hundred eleven".