Base | Representation |
---|---|
bin | 11101000110111001011… |
… | …10001111111010111001 |
3 | 10112121112011102202111101 |
4 | 32203130232033322321 |
5 | 112341234143232100 |
6 | 2043242251131401 |
7 | 132154201454551 |
oct | 16433456177271 |
9 | 3477464382441 |
10 | 1000135524025 |
11 | 356178480120 |
12 | 1419bb443b61 |
13 | 7340a399781 |
14 | 3659a444161 |
15 | 1b0385d686a |
hex | e8dcb8feb9 |
1000135524025 has 24 divisors (see below), whose sum is σ = 1384373653344. Its totient is φ = 710455670400.
The previous prime is 1000135524007. The next prime is 1000135524041. The reversal of 1000135524025 is 5204255310001.
It is not a de Polignac number, because 1000135524025 - 225 = 1000101969593 is a prime.
It is a super-3 number, since 3×10001355240253 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 1000135523984 and 1000135524002.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 42277204 + ... + 42300853.
It is an arithmetic number, because the mean of its divisors is an integer number (57682235556).
Almost surely, 21000135524025 is an apocalyptic number.
It is an amenable number.
1000135524025 is a deficient number, since it is larger than the sum of its proper divisors (384238129319).
1000135524025 is a wasteful number, since it uses less digits than its factorization.
1000135524025 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 84578121 (or 84578116 counting only the distinct ones).
The product of its (nonzero) digits is 6000, while the sum is 28.
The spelling of 1000135524025 in words is "one trillion, one hundred thirty-five million, five hundred twenty-four thousand, twenty-five".
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