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10001383 = 71428769
BaseRepresentation
bin100110001001…
…101111100111
3200211010022121
4212021233213
510030021013
6554210411
7151003360
oct46115747
920733277
1010001383
115711207
123423a07
1320c23a2
141484b67
15d2858d
hex989be7

10001383 has 4 divisors (see below), whose sum is σ = 11430160. Its totient is φ = 8572608.

The previous prime is 10001363. The next prime is 10001399. The reversal of 10001383 is 38310001.

10001383 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 38310001 = 105136451.

It is a cyclic number.

It is not a de Polignac number, because 10001383 - 29 = 10000871 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10001363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 714378 + ... + 714391.

It is an arithmetic number, because the mean of its divisors is an integer number (2857540).

Almost surely, 210001383 is an apocalyptic number.

10001383 is a deficient number, since it is larger than the sum of its proper divisors (1428777).

10001383 is an equidigital number, since it uses as much as digits as its factorization.

10001383 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1428776.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 10001383 is about 3162.4963241085. The cubic root of 10001383 is about 215.4534004893.

Adding to 10001383 its reverse (38310001), we get a palindrome (48311384).

It can be divided in two parts, 10001 and 383, that multiplied together give a palindrome (3830383).

The spelling of 10001383 in words is "ten million, one thousand, three hundred eighty-three".

Divisors: 1 7 1428769 10001383