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10002012107 is a prime number
BaseRepresentation
bin10010101000010101…
…01001011111001011
3221211001112212012212
421110022221133023
5130441003341412
64332253455335
7502600462103
oct112412513713
927731485185
1010002012107
11427296980a
121b317a154b
13c35243279
146ac528203
153d8159222
hex2542a97cb

10002012107 has 2 divisors, whose sum is σ = 10002012108. Its totient is φ = 10002012106.

The previous prime is 10002012089. The next prime is 10002012109. The reversal of 10002012107 is 70121020001.

10002012107 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10002012107 - 212 = 10002008011 is a prime.

Together with 10002012109, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10002012091 and 10002012100.

It is not a weakly prime, because it can be changed into another prime (10002012109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5001006053 + 5001006054.

It is an arithmetic number, because the mean of its divisors is an integer number (5001006054).

Almost surely, 210002012107 is an apocalyptic number.

10002012107 is a deficient number, since it is larger than the sum of its proper divisors (1).

10002012107 is an equidigital number, since it uses as much as digits as its factorization.

10002012107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28, while the sum is 14.

Adding to 10002012107 its reverse (70121020001), we get a palindrome (80123032108).

The spelling of 10002012107 in words is "ten billion, two million, twelve thousand, one hundred seven".