10002012131 has 2 divisors, whose sum is σ = 10002012132. Its totient is φ = 10002012130.

The previous prime is 10002012109. The next prime is 10002012157. The reversal of 10002012131 is 13121020001.

10002012131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (13121020001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10002012131 is a prime.

It is a super-2 number, since 2×10002012131² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10002212131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5001006065 + 5001006066.

It is an arithmetic number, because the mean of its divisors is an integer number (5001006066).

Almost surely, 2^10002012131 is an apocalyptic number.

10002012131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10002012131 is an equidigital number, since it uses as much as digits as its factorization.

10002012131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 10002012131 its reverse (13121020001), we get a palindrome (23123032132).

The spelling of 10002012131 in words is "ten billion, two million, twelve thousand, one hundred thirty-one".