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10002017 is a prime number
BaseRepresentation
bin100110001001…
…111001100001
3200211011012002
4212021321201
510030031032
6554213345
7151005254
oct46117141
920734162
1010002017
115711733
123424255
1320c276c
14148509b
15d28862
hex989e61

10002017 has 2 divisors, whose sum is σ = 10002018. Its totient is φ = 10002016.

The previous prime is 10002007. The next prime is 10002019. The reversal of 10002017 is 71020001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8994001 + 1008016 = 2999^2 + 1004^2 .

It is a cyclic number.

It is not a de Polignac number, because 10002017 - 210 = 10000993 is a prime.

Together with 10002019, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10001989 and 10002007.

It is not a weakly prime, because it can be changed into another prime (10002019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5001008 + 5001009.

It is an arithmetic number, because the mean of its divisors is an integer number (5001009).

Almost surely, 210002017 is an apocalyptic number.

It is an amenable number.

10002017 is a deficient number, since it is larger than the sum of its proper divisors (1).

10002017 is an equidigital number, since it uses as much as digits as its factorization.

10002017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14, while the sum is 11.

The square root of 10002017 is about 3162.5965597907. The cubic root of 10002017 is about 215.4579530120.

Adding to 10002017 its reverse (71020001), we get a palindrome (81022018).

The spelling of 10002017 in words is "ten million, two thousand, seventeen".