10002121411 has 4 divisors (see below), whose sum is σ = 10590481512. Its totient is φ = 9413761312.

The previous prime is 10002121399. The next prime is 10002121433. The reversal of 10002121411 is 11412120001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11412120001 = 461 ⋅24755141.

It is a cyclic number.

It is not a de Polignac number, because 10002121411 - 2²⁹ = 9465250499 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10002121391 and 10002121400.

It is not an unprimeable number, because it can be changed into a prime (10002124411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 294180025 + ... + 294180058.

It is an arithmetic number, because the mean of its divisors is an integer number (2647620378).

Almost surely, 2^10002121411 is an apocalyptic number.

10002121411 is a deficient number, since it is larger than the sum of its proper divisors (588360101).

10002121411 is an equidigital number, since it uses as much as digits as its factorization.

10002121411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 588360100.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 10002121411 its reverse (11412120001), we get a palindrome (21414241412).

The spelling of 10002121411 in words is "ten billion, two million, one hundred twenty-one thousand, four hundred eleven".