Base | Representation |
---|---|
bin | 111011100111100… |
… | …001000101111101 |
3 | 2120201002011220122 |
4 | 323213201011331 |
5 | 4022023334114 |
6 | 243130024325 |
7 | 33533454311 |
oct | 7347410575 |
9 | 2521064818 |
10 | 1000214909 |
11 | 4736602a1 |
12 | 23ab780a5 |
13 | 12c2b3c55 |
14 | 96ba5b41 |
15 | 5cc24e8e |
hex | 3b9e117d |
1000214909 has 2 divisors, whose sum is σ = 1000214910. Its totient is φ = 1000214908.
The previous prime is 1000214881. The next prime is 1000214911. The reversal of 1000214909 is 9094120001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 569776900 + 430438009 = 23870^2 + 20747^2 .
It is an emirp because it is prime and its reverse (9094120001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1000214909 - 28 = 1000214653 is a prime.
It is a Sophie Germain prime.
Together with 1000214911, it forms a pair of twin primes.
It is a Chen prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1000214209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500107454 + 500107455.
It is an arithmetic number, because the mean of its divisors is an integer number (500107455).
Almost surely, 21000214909 is an apocalyptic number.
It is an amenable number.
1000214909 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000214909 is an equidigital number, since it uses as much as digits as its factorization.
1000214909 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 26.
The square root of 1000214909 is about 31626.1744287860. The cubic root of 1000214909 is about 1000.0716312022.
The spelling of 1000214909 in words is "one billion, two hundred fourteen thousand, nine hundred nine".
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