10002553999 has 4 divisors (see below), whose sum is σ = 10009798360. Its totient is φ = 9995309640.

The previous prime is 10002553997. The next prime is 10002554033. The reversal of 10002553999 is 99935520001.

10002553999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10002553999 - 2¹ = 10002553997 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10002553997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3620109 + ... + 3622870.

It is an arithmetic number, because the mean of its divisors is an integer number (2502449590).

Almost surely, 2^10002553999 is an apocalyptic number.

10002553999 is a deficient number, since it is larger than the sum of its proper divisors (7244361).

10002553999 is an equidigital number, since it uses as much as digits as its factorization.

10002553999 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7244360.

The product of its (nonzero) digits is 109350, while the sum is 43.

It can be divided in two parts, 10002 and 553999, that added together give a square (564001 = 751²).

The spelling of 10002553999 in words is "ten billion, two million, five hundred fifty-three thousand, nine hundred ninety-nine".