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10003011313 is a prime number
BaseRepresentation
bin10010101000011100…
…11101011011110001
3221211010102121212111
421110032131123301
5130441232330223
64332331125321
7502612123201
oct112416353361
927733377774
1010003011313
1142734914a9
121b31ba3841
13c35503009
146ac708401
153d82a530d
hex25439d6f1

10003011313 has 2 divisors, whose sum is σ = 10003011314. Its totient is φ = 10003011312.

The previous prime is 10003011289. The next prime is 10003011329. The reversal of 10003011313 is 31311030001.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9996600289 + 6411024 = 99983^2 + 2532^2 .

It is an emirp because it is prime and its reverse (31311030001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10003011313 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10003011293 and 10003011302.

It is not a weakly prime, because it can be changed into another prime (10003011113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5001505656 + 5001505657.

It is an arithmetic number, because the mean of its divisors is an integer number (5001505657).

Almost surely, 210003011313 is an apocalyptic number.

It is an amenable number.

10003011313 is a deficient number, since it is larger than the sum of its proper divisors (1).

10003011313 is an equidigital number, since it uses as much as digits as its factorization.

10003011313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27, while the sum is 13.

Adding to 10003011313 its reverse (31311030001), we get a palindrome (41314041314).

The spelling of 10003011313 in words is "ten billion, three million, eleven thousand, three hundred thirteen".