Base | Representation |
---|---|
bin | 11101000111010001111… |
… | …00001011110111110111 |
3 | 10112122001110010211020100 |
4 | 32203220330023313313 |
5 | 112342144132112210 |
6 | 2043314452405143 |
7 | 132162240663144 |
oct | 16435074136767 |
9 | 3478043124210 |
10 | 1000340504055 |
11 | 356273154702 |
12 | 141a580167b3 |
13 | 734409a8729 |
14 | 365b97613cb |
15 | 1b04b5c65c0 |
hex | e8e8f0bdf7 |
1000340504055 has 12 divisors (see below), whose sum is σ = 1733923540440. Its totient is φ = 533514935472.
The previous prime is 1000340503951. The next prime is 1000340504069. The reversal of 1000340504055 is 5504050430001.
1000340504055 is a `hidden beast` number, since 100 + 0 + 3 + 4 + 0 + 504 + 0 + 55 = 666.
It is not a de Polignac number, because 1000340504055 - 212 = 1000340499959 is a prime.
It is a super-2 number, since 2×10003405040552 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 11114894445 + ... + 11114894534.
It is an arithmetic number, because the mean of its divisors is an integer number (144493628370).
Almost surely, 21000340504055 is an apocalyptic number.
1000340504055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1000340504055 is a deficient number, since it is larger than the sum of its proper divisors (733583036385).
1000340504055 is a wasteful number, since it uses less digits than its factorization.
1000340504055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22229788990 (or 22229788987 counting only the distinct ones).
The product of its (nonzero) digits is 6000, while the sum is 27.
Adding to 1000340504055 its reverse (5504050430001), we get a palindrome (6504390934056).
The spelling of 1000340504055 in words is "one trillion, three hundred forty million, five hundred four thousand, fifty-five".
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