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100034413351132 = 2213311383069339
BaseRepresentation
bin10110101111101100010011…
…101011000101000011011100
3111010012012022021002220021011
4112233230103223011003130
5101102430434304214012
6552431101452145004
730033151005614101
oct2657542353050334
9433165267086234
10100034413351132
11299683a1499237
12b27740a768164
1343a8287967000
141a9b99744caa8
15b871d0abd1a7
hex5afb13ac50dc

100034413351132 has 24 divisors (see below), whose sum is σ = 189641935204400. Its totient is φ = 46169729234928.

The previous prime is 100034413351087. The next prime is 100034413351157. The reversal of 100034413351132 is 231153314430001.

It is a super-2 number, since 2×1000344133511322 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100034413351094 and 100034413351103.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5691525882 + ... + 5691543457.

Almost surely, 2100034413351132 is an apocalyptic number.

It is an amenable number.

100034413351132 is a deficient number, since it is larger than the sum of its proper divisors (89607521853268).

100034413351132 is a wasteful number, since it uses less digits than its factorization.

100034413351132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11383069382 (or 11383069354 counting only the distinct ones).

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 100034413351132 its reverse (231153314430001), we get a palindrome (331187727781133).

The spelling of 100034413351132 in words is "one hundred trillion, thirty-four billion, four hundred thirteen million, three hundred fifty-one thousand, one hundred thirty-two".

Divisors: 1 2 4 13 26 52 169 338 676 2197 4394 8788 11383069339 22766138678 45532277356 147979901407 295959802814 591919605628 1923738718291 3847477436582 7694954873164 25008603337783 50017206675566 100034413351132