1000400121141 has 4 divisors (see below), whose sum is σ = 1333866828192. Its totient is φ = 666933414092.

The previous prime is 1000400121131. The next prime is 1000400121151. The reversal of 1000400121141 is 1411210040001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (1000400121131) and next prime (1000400121151).

It is a cyclic number.

It is not a de Polignac number, because 1000400121141 - 2¹³ = 1000400112949 is a prime.

It is a super-3 number, since 3×1000400121141³ (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1000400121141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1000400121131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166733353521 + ... + 166733353526.

It is an arithmetic number, because the mean of its divisors is an integer number (333466707048).

Almost surely, 2^{1000400121141} is an apocalyptic number.

It is an amenable number.

1000400121141 is a deficient number, since it is larger than the sum of its proper divisors (333466707051).

1000400121141 is an equidigital number, since it uses as much as digits as its factorization.

1000400121141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 333466707050.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 1000400121141 its reverse (1411210040001), we get a palindrome (2411610161142).

The spelling of 1000400121141 in words is "one trillion, four hundred million, one hundred twenty-one thousand, one hundred forty-one".