Base | Representation |
---|---|
bin | 1001000110010100001101… |
… | …1100110001111101111011 |
3 | 1022102101100122202202221211 |
4 | 2101211003130301331323 |
5 | 2302401404233404210 |
6 | 33135454102143551 |
7 | 2051526116530204 |
oct | 221450334617573 |
9 | 38371318682854 |
10 | 10004110450555 |
11 | 32077a05a73a1 |
12 | 1156a44421bb7 |
13 | 5774ca90c3a0 |
14 | 2682b6dd45ab |
15 | 12536ac3438a |
hex | 91943731f7b |
10004110450555 has 8 divisors (see below), whose sum is σ = 12928388890032. Its totient is φ = 7387650794208.
The previous prime is 10004110450553. The next prime is 10004110450561. The reversal of 10004110450555 is 55505401140001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10004110450555 - 21 = 10004110450553 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10004110450553) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 76954695709 + ... + 76954695838.
It is an arithmetic number, because the mean of its divisors is an integer number (1616048611254).
Almost surely, 210004110450555 is an apocalyptic number.
10004110450555 is a deficient number, since it is larger than the sum of its proper divisors (2924278439477).
10004110450555 is a wasteful number, since it uses less digits than its factorization.
10004110450555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 153909391565.
The product of its (nonzero) digits is 10000, while the sum is 31.
Adding to 10004110450555 its reverse (55505401140001), we get a palindrome (65509511590556).
The spelling of 10004110450555 in words is "ten trillion, four billion, one hundred ten million, four hundred fifty thousand, five hundred fifty-five".
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