Base | Representation |
---|---|
bin | 11101000111011100110… |
… | …10011010001100011101 |
3 | 10112122021211220012120222 |
4 | 32203232122122030131 |
5 | 112342341133004432 |
6 | 2043331532251125 |
7 | 132164434232066 |
oct | 16435632321435 |
9 | 3478254805528 |
10 | 1000432313117 |
11 | 35630aa61166 |
12 | 141a82910aa5 |
13 | 73456a11c13 |
14 | 365c7a1d56d |
15 | 1b0546ae112 |
hex | e8ee69a31d |
1000432313117 has 2 divisors, whose sum is σ = 1000432313118. Its totient is φ = 1000432313116.
The previous prime is 1000432313071. The next prime is 1000432313141. The reversal of 1000432313117 is 7113132340001.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 790002770041 + 210429543076 = 888821^2 + 458726^2 .
It is a cyclic number.
It is not a de Polignac number, because 1000432313117 - 220 = 1000431264541 is a prime.
It is a super-2 number, since 2×10004323131172 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1000432013117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500216156558 + 500216156559.
It is an arithmetic number, because the mean of its divisors is an integer number (500216156559).
Almost surely, 21000432313117 is an apocalyptic number.
It is an amenable number.
1000432313117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000432313117 is an equidigital number, since it uses as much as digits as its factorization.
1000432313117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 1000432313117 its reverse (7113132340001), we get a palindrome (8113564653118).
The spelling of 1000432313117 in words is "one trillion, four hundred thirty-two million, three hundred thirteen thousand, one hundred seventeen".
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