Base | Representation |
---|---|
bin | 1001000110010101000010… |
… | …1111000010010101100001 |
3 | 1022102101221012011201210111 |
4 | 2101211100233002111201 |
5 | 2302402333313340001 |
6 | 33135532143331321 |
7 | 2051534464206520 |
oct | 221452057022541 |
9 | 38371835151714 |
10 | 10004333340001 |
11 | 32078a53a3550 |
12 | 1156aa6bb0b41 |
13 | 577534b4c030 |
14 | 2682d88544b7 |
15 | 1253805b0851 |
hex | 91950bc2561 |
10004333340001 has 32 divisors (see below), whose sum is σ = 13446851846400. Its totient is φ = 7188177530880.
The previous prime is 10004333339999. The next prime is 10004333340059.
It is a happy number.
10004333340001 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 10004333340001 - 21 = 10004333339999 is a prime.
It is not an unprimeable number, because it can be changed into a prime (10004333310001) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4449156 + ... + 6309013.
It is an arithmetic number, because the mean of its divisors is an integer number (420214120200).
Almost surely, 210004333340001 is an apocalyptic number.
10004333340001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
10004333340001 is a deficient number, since it is larger than the sum of its proper divisors (3442518506399).
10004333340001 is a wasteful number, since it uses less digits than its factorization.
10004333340001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10759129.
The product of its (nonzero) digits is 1296, while the sum is 22.
It can be divided in two parts, 1000433 and 3340001, that added together give a palindrome (4340434).
The spelling of 10004333340001 in words is "ten trillion, four billion, three hundred thirty-three million, three hundred forty thousand, one".
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