Base | Representation |
---|---|
bin | 11101000111011100111… |
… | …10101101010100000101 |
3 | 10112122021221000110101120 |
4 | 32203232132231110011 |
5 | 112342341430040010 |
6 | 2043332012344153 |
7 | 132164446634346 |
oct | 16435636552405 |
9 | 3478257013346 |
10 | 1000433440005 |
11 | 35631066087a |
12 | 141a83175059 |
13 | 73457017b0c |
14 | 365c7c340cd |
15 | 1b054832e70 |
hex | e8ee7ad505 |
1000433440005 has 32 divisors (see below), whose sum is σ = 1605299076480. Its totient is φ = 532029876480.
The previous prime is 1000433439991. The next prime is 1000433440007. The reversal of 1000433440005 is 5000443340001.
It is not a de Polignac number, because 1000433440005 - 210 = 1000433438981 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1000433440007) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 34736151 + ... + 34764939.
It is an arithmetic number, because the mean of its divisors is an integer number (50165596140).
Almost surely, 21000433440005 is an apocalyptic number.
1000433440005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1000433440005 is a deficient number, since it is larger than the sum of its proper divisors (604865636475).
1000433440005 is a wasteful number, since it uses less digits than its factorization.
1000433440005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35381.
The product of its (nonzero) digits is 2880, while the sum is 24.
Adding to 1000433440005 its reverse (5000443340001), we get a palindrome (6000876780006).
The spelling of 1000433440005 in words is "one trillion, four hundred thirty-three million, four hundred forty thousand, five".
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