Base | Representation |
---|---|
bin | 10010101000100111… |
… | …00001110100011111 |
3 | 221211012221010111002 |
4 | 21110103201310133 |
5 | 130442102334444 |
6 | 4332415420515 |
7 | 502626326003 |
oct | 112423416437 |
9 | 27735833432 |
10 | 10004339999 |
11 | 4274209795 |
12 | 1b3252473b |
13 | c35879a14 |
14 | 6ac972703 |
15 | 3d8468d4e |
hex | 2544e1d1f |
10004339999 has 2 divisors, whose sum is σ = 10004340000. Its totient is φ = 10004339998.
The previous prime is 10004339993. The next prime is 10004340019. The reversal of 10004339999 is 99993340001.
10004339999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10004339999 - 216 = 10004274463 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10004339993) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002169999 + 5002170000.
It is an arithmetic number, because the mean of its divisors is an integer number (5002170000).
Almost surely, 210004339999 is an apocalyptic number.
10004339999 is a deficient number, since it is larger than the sum of its proper divisors (1).
10004339999 is an equidigital number, since it uses as much as digits as its factorization.
10004339999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 236196, while the sum is 47.
The spelling of 10004339999 in words is "ten billion, four million, three hundred thirty-nine thousand, nine hundred ninety-nine".
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