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10004341331300 = 2252100043413313
BaseRepresentation
bin1001000110010101000100…
…1101100001010101100100
31022102101221202012201210112
42101211101031201111210
52302402342340100200
633135533030512152
72051534622142001
oct221452115412544
938371852181715
1010004341331300
1132078a9961528
121156aa9805658
135775366b9504
142682d99348a8
1512538113d535
hex91951361564

10004341331300 has 18 divisors (see below), whose sum is σ = 21709420689138. Its totient is φ = 4001736532480.

The previous prime is 10004341331297. The next prime is 10004341331321. The reversal of 10004341331300 is 313314340001.

It can be written as a sum of positive squares in 3 ways, for example, as 35570714404 + 9968770616896 = 188602^2 + 3157336^2 .

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 50021706557 + ... + 50021706756.

Almost surely, 210004341331300 is an apocalyptic number.

10004341331300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

10004341331300 is an abundant number, since it is smaller than the sum of its proper divisors (11705079357838).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10004341331300 is a wasteful number, since it uses less digits than its factorization.

10004341331300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100043413327 (or 100043413320 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 10004341331300 its reverse (313314340001), we get a palindrome (10317655671301).

The spelling of 10004341331300 in words is "ten trillion, four billion, three hundred forty-one million, three hundred thirty-one thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 100043413313 200086826626 400173653252 500217066565 1000434133130 2000868266260 2501085332825 5002170665650 10004341331300