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10004413231213 is a prime number
BaseRepresentation
bin1001000110010101010101…
…1111110011000001101101
31022102102010202111121221021
42101211111133303001231
52302403014241344323
633135544115534141
72051536454240512
oct221452537630155
938372122447837
1010004413231213
1132079364aaa45
121156b098ba351
13577548571a3b
142683052cd309
151253875e205d
hex919557f306d

10004413231213 has 2 divisors, whose sum is σ = 10004413231214. Its totient is φ = 10004413231212.

The previous prime is 10004413231207. The next prime is 10004413231247. The reversal of 10004413231213 is 31213231440001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10004233724809 + 179506404 = 3162947^2 + 13398^2 .

It is a cyclic number.

It is not a de Polignac number, because 10004413231213 - 217 = 10004413100141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10004413231913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002206615606 + 5002206615607.

It is an arithmetic number, because the mean of its divisors is an integer number (5002206615607).

Almost surely, 210004413231213 is an apocalyptic number.

It is an amenable number.

10004413231213 is a deficient number, since it is larger than the sum of its proper divisors (1).

10004413231213 is an equidigital number, since it uses as much as digits as its factorization.

10004413231213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 10004413231213 its reverse (31213231440001), we get a palindrome (41217644671214).

The spelling of 10004413231213 in words is "ten trillion, four billion, four hundred thirteen million, two hundred thirty-one thousand, two hundred thirteen".