100048511 has 2 divisors, whose sum is σ = 100048512. Its totient is φ = 100048510.

The previous prime is 100048493. The next prime is 100048513. The reversal of 100048511 is 115840001.

It is a strong prime.

It is an emirp because it is prime and its reverse (115840001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100048511 is a prime.

Together with 100048513, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100048513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50024255 + 50024256.

It is an arithmetic number, because the mean of its divisors is an integer number (50024256).

Almost surely, 2^100048511 is an apocalyptic number.

100048511 is a deficient number, since it is larger than the sum of its proper divisors (1).

100048511 is an equidigital number, since it uses as much as digits as its factorization.

100048511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 160, while the sum is 20.

The square root of 100048511 is about 10002.4252559067. The cubic root of 100048511 is about 464.2339272664.

Adding to 100048511 its reverse (115840001), we get a palindrome (215888512).

The spelling of 100048511 in words is "one hundred million, forty-eight thousand, five hundred eleven".