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100054413119 is a prime number
BaseRepresentation
bin101110100101110110…
…1010010111100111111
3100120020222000211000102
41131023231102330333
53114402412204434
6113544145151315
710141304323223
oct1351355227477
9316228024012
10100054413119
1139484120521
121748402b53b
139586b8175b
144bb2386783
152908dd707e
hex174bb52f3f

100054413119 has 2 divisors, whose sum is σ = 100054413120. Its totient is φ = 100054413118.

The previous prime is 100054413113. The next prime is 100054413139. The reversal of 100054413119 is 911314450001.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100054413119 is a prime.

It is a super-2 number, since 2×1000544131192 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100054413091 and 100054413100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100054413113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50027206559 + 50027206560.

It is an arithmetic number, because the mean of its divisors is an integer number (50027206560).

Almost surely, 2100054413119 is an apocalyptic number.

100054413119 is a deficient number, since it is larger than the sum of its proper divisors (1).

100054413119 is an equidigital number, since it uses as much as digits as its factorization.

100054413119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 29.

The spelling of 100054413119 in words is "one hundred billion, fifty-four million, four hundred thirteen thousand, one hundred nineteen".