Search a number
-
+
1001000100053 is a prime number
BaseRepresentation
bin11101001000100000100…
…00010110000011010101
310112200202102021202211202
432210100100112003111
5112400022011200203
62043504134042245
7132214500314432
oct16442020260325
93480672252752
101001000100053
11356581507968
12142000aa9385
137351753c415
143663d1bcb89
151b089467388
hexe9104160d5

1001000100053 has 2 divisors, whose sum is σ = 1001000100054. Its totient is φ = 1001000100052.

The previous prime is 1001000099993. The next prime is 1001000100077. The reversal of 1001000100053 is 3500010001001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 674275826449 + 326724273604 = 821143^2 + 571598^2 .

It is an emirp because it is prime and its reverse (3500010001001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1001000100053 is a prime.

It is a super-2 number, since 2×10010001000532 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1001000100953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500500050026 + 500500050027.

It is an arithmetic number, because the mean of its divisors is an integer number (500500050027).

Almost surely, 21001000100053 is an apocalyptic number.

It is an amenable number.

1001000100053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001000100053 is an equidigital number, since it uses as much as digits as its factorization.

1001000100053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15, while the sum is 11.

Adding to 1001000100053 its reverse (3500010001001), we get a palindrome (4501010101054).

The spelling of 1001000100053 in words is "one trillion, one billion, one hundred thousand, fifty-three".