100100021100113 has 2 divisors, whose sum is σ = 100100021100114. Its totient is φ = 100100021100112.

The previous prime is 100100021100089. The next prime is 100100021100127. The reversal of 100100021100113 is 311001120001001.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99885492798529 + 214528301584 = 9994273^2 + 463172^2 .

It is an emirp because it is prime and its reverse (311001120001001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100100021100113 - 2¹² = 100100021096017 is a prime.

It is a super-2 number, since 2×100100021100113² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100100021100094 and 100100021100103.

It is not a weakly prime, because it can be changed into another prime (100100021100613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50050010550056 + 50050010550057.

It is an arithmetic number, because the mean of its divisors is an integer number (50050010550057).

Almost surely, 2^{100100021100113} is an apocalyptic number.

It is an amenable number.

100100021100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100100021100113 is an equidigital number, since it uses as much as digits as its factorization.

100100021100113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 100100021100113 its reverse (311001120001001), we get a palindrome (411101141101114).

The spelling of 100100021100113 in words is "one hundred trillion, one hundred billion, twenty-one million, one hundred thousand, one hundred thirteen".